BHU PMT BHU PMT Solved Paper-2004

  • question_answer
    The coefficient of mutual inductance, when magnetic flux is \[2\times {{10}^{-2}}\] Wb and change in current is 0.01 A, is:                                                                                                                                                                                                         [BHU PMT-2004]

    A)  2 H                                        

    B)  3 H

    C)  4 H                                        

    D)  8 H

    Correct Answer: A

    Solution :

                     Coefficient of mutual induction of two coils is equal to the number of magnetic flux \[\left( \phi  \right)\] linkages in one coil when a unit current \[\left( i \right)\] flows in the other \[\therefore \]  \[M=\frac{\phi }{i}henry\] Given, \[\phi =2\times {{10}^{-2}}\,Wb,\,i=0.01\,A\]                                 \[M=\frac{2\times {{10}^{-2}}}{0.01}=2\,H\] Note: The coefficient of mutual induction of two coils in also equal to the numerical value of induced emf in one coil when rate of change of current in the other coil is units.


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