A) 1 : 2
B) 2 : 1
C) 1 : 4
D) 4 : 1
Correct Answer: D
Solution :
Key Idea: Resistance in series combination is more than resistance in parallel combination. The amount of heat produced across a wire when current \[i\] is \[H={{i}^{2}}\,Rt\] Where \[R\] is resistance of wire. In series equivalent resistance is \[{{R}_{s}}=R+R=2R\] In parallel, equivalent resistance is \[{{R}_{p}}=\frac{R}{2}.\] \[\therefore \] \[\frac{{{H}_{s}}}{{{H}_{p}}}=\frac{2\,R}{R/2}=4\] \[\therefore \] \[{{H}_{s}}:{{H}_{p}}=4:1\]
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