A) 1/3
B) 2/5
C) 3/4
D) 3/5
Correct Answer: B
Solution :
Efficiency of heat engine is the fraction of the total heat supplied to the engine which is converted into work that is \[\eta =1-\frac{{{Q}_{2}}}{{{Q}_{1}}}\] \[=1-\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\Rightarrow \] \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\] Given, \[{{T}_{1}}={{227}^{\circ }}C=227+273=500\,K\] \[{{T}_{2}}={{27}^{\circ }}C=273+27=300\,K\] \[\therefore \] \[\eta =\frac{500-300}{500}=\frac{200}{500}=\frac{2}{5}\]
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