A) Ethylene glycol
B) Ethylene oxide
C) Ethylene dinitrate
D) Ethane
Correct Answer: A
Solution :
\[\underset{Ethylene}{\mathop{{{H}_{2}}C=C{{H}_{2}}}}\,+HOCl\xrightarrow[{}]{{}}\underset{(Ethylene\text{ }chlorohydrin)}{\mathop{\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{{{H}_{2}}C}}\,-C{{H}_{2}}OH}}\,\] \[\xrightarrow[{}]{NaHC{{O}_{3}}}\underset{Ethylene\text{ }glycol}{\mathop{\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{{{H}_{2}}C}}\,-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,}}\,+NaCl+C{{O}_{2}}\]
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