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BHU PMT BHU PMT Solved Paper-2002

  • question_answer
    An open knife edge of mass \[F{{v}^{-1}}\] is dropped from a height \[E{{v}^{-2}}\] on a wooden floor. If the blade penetrates upto the depth \[E{{v}^{2}}\] in to the wood, the average resistance offered by the wood to the knife edge is:                             [BHU PMT-2002]

    A)                  \[n-p-n\]                           

    B)                  \[{{K}_{\gamma }}-X-ray\]

    C)                  \[n=4\,to\,n=1\]                            

    D)                  \[n=3\,to\,n=1\]

    Correct Answer: A

    Solution :

                     Key Idea: Law of conservation of energy is valid here.                 Potential energy is energy result from position or configuration of knife edge, this potential energy is utilized in doing work against resistive force offered by the wood.                 Hence, potential energy=work done                 \[Velocity=\left[ L{{T}^{-1}} \right]\]                       \[\therefore \]                 \[\Rightarrow \]                               \[\left[ M \right]=\left[ E\,{{v}^{-2}} \right]\,\]                                                 \[K\]


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