A) \[{{K}_{4}}[Fe{{(CN)}_{6}}]\]
B) \[{{K}_{3}}[Fe{{(CN)}_{6}}]\]
C) \[Fe{{(CNS)}_{3}}\]
D) \[F{{e}_{4}}{{[Fe{{(CN)}_{6}}]}_{3}}\]
Correct Answer: D
Solution :
\[\underset{Ferric\,ion}{\mathop{4F{{e}^{3+}}}}\,+3{{K}_{4}}[Fe{{(CN)}_{6}}]\xrightarrow{{}}\underset{\begin{smallmatrix} Ferric\text{ }ferrocyanide \\ \,\,\,\,\,\,(\Pr ussian\text{ }blue) \end{smallmatrix}}{\mathop{F{{e}_{4}}{{[Fe{{(CN)}_{6}}]}_{3}}}}\,\] \[+12{{K}^{+}}\] Ferric ions with potassium ferrocyanide produce prussian blue colour of ferric ferrocyanide.
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