A) maltase
B) zymase
C) diastase
D) invertase
Correct Answer: B
Solution :
\[\underset{Maltose}{\mathop{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}\,+{{H}_{2}}O\xrightarrow[{}]{Maltase}\underset{Glucose}{\mathop{2{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\] \[\underset{Glu\cos e\text{ }or\text{ }fructose}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\xrightarrow[{}]{Zymase}\underset{Ethyl\text{ }alcohol}{\mathop{2{{C}_{2}}{{H}_{5}}OH}}\,+2C{{O}_{2}}\] \[\underset{Starch}{\mathop{2{{({{C}_{6}}{{H}_{10}}{{O}_{5}})}_{n}}}}\,+n{{H}_{2}}O\xrightarrow[{}]{Diastase}\underset{Glu\cos e}{\mathop{2{{C}_{12}}{{H}_{22}}{{O}_{11}}}}\,\] \[\underset{Sucrose}{\mathop{{{C}_{6}}{{H}_{22}}{{O}_{11}}}}\,+{{H}_{2}}O\xrightarrow[{}]{Invertase}\underset{Glu\cos e}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\] \[\underset{Fructose}{\mathop{+{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\]
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