A) 2-ethyl-but-2-ene
B) 4-ethyl-pent-2-ene
C) 4-methyl-hex-2-ene
D) 5-methyl-pen-2-ene
Correct Answer: C
Solution :
\[\underset{4-methyl\text{ }hex-2-ene}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} ^{6}{{C}_{2}}{{H}_{5}} \\ 5| \end{smallmatrix}}{\mathop{\underset{4}{\mathop{CH}}\,}}\,-\underset{3}{\mathop{CH}}\,=\underset{2}{\mathop{CH}}\,-\underset{1}{\mathop{C{{H}_{3}}}}\,}}\,\]
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