A) \[6.123\times {{10}^{23}}\]
B) \[6.312\times {{10}^{22}}\]
C) \[6.023\times {{10}^{22}}\]
D) \[6.076\times {{10}^{23}}\]
Correct Answer: C
Solution :
\[\because \]108 g of silver contains\[=6.02\times {{10}^{23}}\] atoms of Ag \[\therefore \]10.8 g of silver contains\[=\frac{6.023\times {{10}^{23}}}{108}\times 10.8\] \[=6.023\times {{10}^{22}}atoms\]
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