A) \[{{I}_{b}}=35\mu A=35\times {{10}^{-6}}A\]
B) \[\therefore \]
C) \[{{R}_{b}}=\frac{7}{35\times {{10}^{-6}}}\]
D) \[=200\times {{10}^{3}}\,\Omega \]
Correct Answer: C
Solution :
Key Idea: The value of \[g\] decrease on going above and below the earth?s surface. The value of \[g\]at a height \[h\] above the earth?s surface of radius \[R\] is given by \[g'=g\left( 1-\frac{Zh}{R} \right)\] ?(1) The value of \[g\] at a depth \[x\] below the surface of earth is given by \[g'\,\,'=g\left( 1-\frac{x}{R} \right)\] ?(2) Given, \[g'=g'\,'\] \[\therefore \] \[g\left( 1-\frac{2h}{R} \right)=g\left( 1-\frac{x}{R} \right)\] \[\Rightarrow \] \[x=2h\]
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