BHU PMT BHU PMT Solved Paper-2002

  • question_answer
    If the earth's field induction at a place is 0.36 Gauss and the angle of dip is 60°. The Horizontal and vertical component of the field Will be respectively:                                             [BHU PMT-2002]

    A)                  \[\text{0}\text{.102}\]

    B)                  \[\text{0}\text{.51 eV}\]

    C)                  \[\text{20 eV}\]

    D)                  \[\text{1020 eV}\]

    Correct Answer: A

    Solution :

                     The angle of dip at a place is the angle between the direction of earth?s magnetic field and the horizontal in the magnetic meridian at that place. The earth?s magnetic field \[{{B}_{e}}\] may be resolved into two components.                                                 \[H={{B}_{e}}\,\cos \,\,\theta \]                                                 \[V={{B}_{e}}\,\sin \,\,\theta \]                 Given, \[\theta ={{60}^{\circ }},\,{{B}_{e}}=0.36\,G.\]                 \[H=0.36\,\,\cos \,\,{{60}^{\circ }}=0.36\times \frac{1}{2}=0.18\,\,gauss\]                 \[V=0.36\,\,\cos \,\,{{60}^{\circ }}=0.36\times \frac{\sqrt{3}}{2}=0.18\,\sqrt{3}\,gauss\]Note : The angle of dip changes not only from place, but also at the same place  from time to time irregularly.


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