A) constant
B) Four times
C) two times
D) half
Correct Answer: C
Solution :
The fringe width \[2.4\times {{10}^{-5}}\,\,Wb\] is given by \[0.2\,c{{m}^{2}}\] Where \[1788\]is distance between the screen and slits, \[1192\] is distance between coherent sources, and \[596\] is wavelength. Given, \[298\] \[12.981\times {{10}^{2}}\,\,{{m}^{2}}\] \[9.281\times {{10}^{9}}\,\,{{m}^{2}}\] \[1.69\times {{10}^{12}}\,\,{{m}^{2}}\] \[4.529\times {{10}^{9}}\,\,{{m}^{2}}\] Note: Fringe width of all bright and dark tringes is the same, provided the distance \[5\,\,m/s\] of the screen from the slits is much larger that the separation \[165\,\,Hz\] between the slits.
You need to login to perform this action.
You will be redirected in
3 sec
