BHU PMT BHU PMT Solved Paper-2002

  • question_answer
    An electromagnetic wave passing through Vacuum is described by the equation:                 \[\frac{16\,R}{9}\] And \[\frac{9\,R}{16}\] then:                                             [BHU PMT-2002]

    A)                  \[n\]                                    

    B)                  \[\frac{3}{2}n\]

    C)                  \[\frac{n}{2}\]                 

    D)                  \[2n\]

    Correct Answer: D

    Solution :

                     The wave equation for a plane electromagnetic wave travelling in the x-direction space is \[l\]                 Both electric field and magnetic field are perpendicular to the direction of travel x. The symbol c represents the speed of light. The form of a plane wave solution for electric field is                                 \[R=\rho \frac{l}{A}\]                     ?(1)                 And magnetic field is                 \[\times \]                          ?(2)                 To be consistent with Maxwell?s equation, these solutions must be related by                                 \[lA\]                                     ?(3)                 And velocity of light is given by                                 \[{{l}_{1}}{{A}_{1}}={{l}_{2}}{{A}_{2}}\]                 Also, \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{{{A}_{2}}}{{{A}_{1}}}=\frac{\pi {{\left( \frac{3r}{4} \right)}^{2}}}{\pi \,{{r}^{2}}}=\frac{9}{16}\]                 \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\times \frac{{{A}_{2}}}{{{A}_{1}}}=\frac{9}{16}\times \frac{9}{16}=\frac{81}{256}\]                      \[\Rightarrow \]                 From Eq. (3), we have                                 \[{{R}_{2}}=\frac{256\,\,{{R}_{1}}}{81}=\frac{256R}{81}\]                 \[l\]        \[n=\frac{v}{2l}\]


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