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BHU PMT BHU PMT Solved Paper-2002

  • question_answer
    The equation of wave motion (with in second and \[\sqrt{{{\omega }_{2}}}:\sqrt{{{\omega }_{1}}}\] in meter) is given by \[m\] The velocity of wave will be:                                  [BHU PMT-2002]

    A)                  \[a\]                    

    B)                  \[\mu \]

    C)                  \[g\left( \cos \,\,a-\mu \,\,\sin \,\,a \right)\]                    

    D)                  \[g\left( sin\,\,a-\mu \,\,\cos \,\,a \right)\]

    Correct Answer: D

    Solution :

                     Key Idea: Compare the given equation of wave with standard one.                 The standard equation of wave motion is                 \[Q=\Delta U+W\]             ?(1)                 Where \[\left( \Delta U=0 \right)\] is velocity, \[\therefore \] is wavelength and \[Q=W\] is phase difference.                 \[k\]  ?(2)                 Comparing Eq. (1) with Eq. (2), we get                                                 \[I=M\,\,{{k}^{2}}\]                 And                        \[I\]                 \[M\]                    \[J=I\omega =\text{constant}\]


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