A) Molarity
B) Molality
C) Normality
D) Formality
Correct Answer: B
Solution :
\[Molarity=\frac{moles\text{ }of\text{ }solute}{volume\text{ }of\text{ }solution\text{ }in\text{ }litre}\] \[Molarity=\frac{moles\text{ }of\text{ }solute}{mass\text{ }of\text{ }solvent\text{ }in\text{ }kg}\] \[Normality=\frac{gram\text{ }equivalents\text{ }of\text{ }solute}{volume\text{ }of\text{ }solution\text{ }in\text{ }litre}\] \[Formality=\frac{formula\text{ }weight}{volume\text{ }of\text{ }solution\text{ }in\text{ }litre}\] \[\because \] molality does not involve volume of solution. \[\therefore \] it does not change with temperature.
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