A) mole fraction of a solute
B) mole fraction of a solvent
C) moles of a solute
D) moles of a solvent
Correct Answer: A
Solution :
Key Idea: According to Raoult's law' the partial pressure of any volatile, component of a solution at any temperature is equal to the vapour pressure of pure component multiplied by mole fraction of the component in the solution. \[{{P}_{A}}=P_{A}^{o}{{x}_{A}}\] where,\[{{P}_{A}}=\]vapour pressure of component A \[P_{A}^{o}=\]vapour pressure of pure component \[{{x}_{A}}=\]mole fraction of component A. \[\frac{{{P}_{A}}-P_{A}^{o}}{P_{A}^{o}}={{x}_{A}}\] So, it is equal to the mole fraction of a solute.
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