A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
Key Idea: Write the electronic configuration of\[O_{2}^{2+}\]and then find bond order by using formula: Bond order no. of \[\overline{e}\]in bonding M.O. \[=\frac{no.\text{ }of\text{ }\overline{e}\text{ }in\text{ }antibonding\text{ }M.O.}{2}\] \[O_{2}^{2+}(14)=\sigma 1{{s}^{2}},{{\sigma }^{*}}1{{s}^{2}},\sigma 2{{s}^{2}},{{\sigma }^{*}}2{{s}^{2}},\sigma 2p_{z}^{2},\] \[\pi 2p_{x}^{2},\pi 2p_{y}^{2}\] \[Bond\text{ }order=\frac{8-2}{2}\] \[=\frac{6}{2}=3\]
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