A) \[sp\]
B) \[s{{p}^{2}}\]
C) \[s{{p}^{3}}\]
D) \[s{{p}^{2}}\]and\[s{{p}^{3}}\]
Correct Answer: B
Solution :
Key Idea:\[s{{p}^{3}}\]hybridisation-carbon has\[4\sigma \]bond\[s{{p}^{2}}\]hybridisation-carbon has\[3\sigma \]and\[1\pi \]bonds sp hybridisation-carbon has\[2\sigma \]and\[2\pi \] bonds. \[H-\underset{1}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,=\underset{2}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,-\underset{3}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,=\underset{4}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,-H\] \[\begin{align} & 3\sigma ,1\pi \,\,\,\,\,3\sigma ,1\pi \,\,\,\,\,\,3\sigma ,1\pi \,\,\,\,\,\,3\sigma ,1\pi \\ & \,\,\,\,\,s{{p}^{2}}~~~\,\,\,\,\,\,\,\,s{{p}^{2}}~~~\,\,\,\,\,\,\,\,\,s{{p}^{2}}~~~\,\,\,\,\,\,\,\,\,s{{p}^{2}} \\ \end{align}\]
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