A) produce electrophile
B) produce nucleophile
C) absorb water
D) absorb\[HCl\]
Correct Answer: A
Solution :
During Friedel-Craft reaction alkyl or acyl group replaces hydrogen of benzene ring. Anhydrous\[AlC{{l}_{3}}\] produces electrophile. \[RCl+\underset{Anhy.\,AlC{{l}_{3}}}{\mathop{AlC{{l}_{3}}}}\,{{R}^{+}}+\underset{Electorphile}{\mathop{AlCl_{4}^{-}}}\,\] \[{{R}^{+}}+{{C}_{6}}{{H}_{6}}\xrightarrow[{}]{{}}{{C}_{6}}{{H}_{5}}Cl+{{H}^{+}}\] \[AlCl_{4}^{-}+{{H}^{+}}\xrightarrow[{}]{{}}AlC{{l}_{3}}+HCl\]
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