A) 0.08 atm
B) 8.1 atm
C) 0.8 atm
D) 9.1 aim
Correct Answer: C
Solution :
Key Idea: Use formula\[PV=nRT\]to solve the problem. P = osmotic pressure = ? \[V=150\text{ }mL=0.15\text{ }L\] \[n=no.\text{ }of\text{ }moles=\frac{mass\text{ }of\text{ }solute}{molecular\text{ }mass\text{ }of\text{ }solute}\] \[=\frac{1.75\,g}{342}\] \[=0.005\] \[R=0.0821\] \[T=17{}^\circ C=17+273=290\text{ }K\] \[PV=nRT\] \[=\frac{0.005\times 0.0821\times 290}{0.15}\] \[=0.8\text{ }atm\]
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