A) \[[Ne]3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }3{{d}^{1}}\text{ }4{{s}^{2}}\]
B) \[[Ne]3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }3{{d}^{2}}\text{ }4{{s}^{1}}\]
C) \[[Ne]3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }3{{d}^{5}}\,4{{s}^{1}}\]
D) \[[Ne]3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }4{{s}^{2}}\text{ }3{{d}^{4}}\]
Correct Answer: C
Solution :
The correct configuration of chromium is \[[Ne]\,3{{s}^{2}},\text{ }3{{p}^{6}},\text{ }3{{d}^{5}},\text{ }4{{s}^{1}}\] It is due to the extra stability of exactly half filled orbitals.
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