BHU PMT BHU PMT Solved Paper-2001

  • question_answer
    If 1 g of hydrogen is converted into 0.993 g of Helium, in the thermo nuclear reaction, the Energy released in the reaction is:

    A)  \[63\times {{10}^{20}}\,J\]                         

    B)  \[63\times {{10}^{14}}\,J\]

    C)  \[63\times {{10}^{10}}\,J\]                         

    D)  \[63\times {{10}^{7}}\,J\]

    Correct Answer: C

    Solution :

    Key-Idea : Einstein?s mass-energy relation gives the conversion of mass into energy. If a substance loses an amount \[\Delta \,m\] of its mass, an Equivalent amount \[\Delta \,E\] of energy is produced. \[\Delta \,E=\left( \Delta m \right){{c}^{2}}\] Where \[c\] is speed of light. This is Einstein?s mass energy relation. Given,   \[{{m}_{1}}=1g=1\times {{10}^{-3}}\,\,kg\]                                 \[{{m}_{2}}=0.993g=0.993\times {{10}^{-3}}\,\,kg\] \[\therefore \]\[\Delta \,m={{m}_{1}}-{{m}_{2}}=\left( 1\times {{10}^{-3}} \right)-\left( 0.993\times {{10}^{-3}} \right)\]                                                                 \[=0.007\times {{10}^{-3}}\]                                                                 \[=7\times {{10}^{-6}}\,\,kg\] \[E=7\times {{10}^{-6}}\times {{\left( 3\times {{10}^{8}} \right)}^{2}}\] \[E=63\times {{10}^{10}}\,\,J\]


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