A) \[3.0\times {{10}^{-19}}/{{m}^{3}}\]
B) \[5\times {{10}^{9}}/{{m}^{3}}\]
C) \[4.5\times {{10}^{22}}/{{m}^{3}}\]
D) \[1.5\times {{10}^{16}}/{{m}^{3}}\]
Correct Answer: B
Solution :
Key Idea: Law of mass-action can be used to achieve the required result. From law of mass-action \[n_{e}^{'}\,n_{h}^{'}=n_{i}^{2}\] \[\Rightarrow \] \[n_{e}^{'}=\frac{n_{i}^{2}}{{{n}_{h}}}\] Given, \[{{n}_{i}}=1.5\times {{10}^{16}}\,{{m}^{3}}\] \[\therefore \] \[n_{e}^{'}=\frac{{{\left( 1.5\times {{10}^{16}} \right)}^{2}}}{4.5\times {{10}^{22}}}\] \[n_{e}^{'}=5\times {{10}^{9}}/{{m}^{3}}\]
You need to login to perform this action.
You will be redirected in
3 sec
