A) \[24\mu C\]
B) \[480\,\mu C\]
C) \[600\,\mu C\]
D) \[120\,\mu C\]
Correct Answer: B
Solution :
The capacitance \[\left( C \right)\] of a conductor is defined as the ratio of the charge \[\left( Q \right)\] given to the rise in the potential \[\left( V \right)\] of the conductor. \[\therefore \] \[Q=CV\] When \[{{C}_{1}}=10\mu F,\,\,V=12\,volt\] \[\therefore \] \[{{Q}_{1}}=\left( 10\times 12 \right)\mu C=120\mu C\] \[{{C}_{2}}=K{{C}_{1}}=5\times 10=50\mu F\] Also, \[{{Q}_{2}}=50\times 12=600\mu C\] Hence, additional charge \[\Delta Q={{Q}_{2}}-{{Q}_{1}}=\left( 600-120 \right)\mu C=480\mu C\]
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