A) \[3.2\times {{10}^{-6}}\] Per sec
B) \[5\times {{10}^{17}}\,Per\,\sec \]
C) \[2\times {{10}^{17}}\,Per\,\sec \]
D) \[2\times {{10}^{18}}\,Per\,\sec \]
Correct Answer: B
Solution :
For the most favorable collision in which the electron loses, the whole of its energy in a single collision with the target atom, an \[\text{X}-\text{ray}\]photon of maximum energy \[hv\] is emitted \[E=hv\] Where \[h\] is Planck?s constant and\[v\] is frequency. Given, \[E=2\,\,ke\,V=2\times {{10}^{3}}\times 1.6\times {{10}^{-19}}\,J\] \[\Rightarrow \] \[v=\frac{E}{h}=\frac{2\times {{10}^{3}}\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-34}}}\] \[=9.84\times {{10}^{17}}\] \[=5\times {{10}^{17}}/s\] Note: Since, energy \[\propto \] frequency, higher the frequency.
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