A) \[{{10}^{-17}}\,\,{{\mu }_{0}}\]
B) \[{{10}^{-11}}\,\,{{\mu }_{0}}\]
C) \[{{10}^{-7}}\,\,{{\mu }_{0}}\]
D) \[{{10}^{-3}}\,\,{{\mu }_{0}}\]
Correct Answer: A
Solution :
The magnetic field at the center of a circular coil carrying current \[i\] and radius \[a\] is \[B=\frac{{{\mu }_{0}}\,i}{2a}\] Also if the charge carried by the free electrons passing through a section of the wire in \[t\]seconds be \[q\], then the strength of current in the wire is \[i=\frac{q}{t}=q\times \]Frequency Given, \[q=100\,\,e=100\times 1.6\times {{10}^{-19}}\,C\] \[=1.6\times {{10}^{-17}}\,C\] \[\therefore \]\[i=1.6\times {{10}^{-17}}\times 1=1.6\times {{10}^{-17}}\,A\] \[\therefore \]\[B={{\mu }_{0}}\frac{1.6\times {{10}^{-17}}}{2\times 0.8}={{10}^{-17}}\mu {{\,}_{0}}\]
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