BHU PMT BHU PMT (Screening) Solved Paper-2011

  • question_answer
    A radioactive element with half-life 6.5 h has \[48\times {{10}^{19}}\]atoms. Number of atoms left after 26 h.

    A)  \[3\times {{10}^{19}}\]                

    B)  \[6\times {{10}^{19}}\]

    C)   \[12\times {{10}^{19}}\]             

    D) \[24\times {{10}^{19}}\]

    Correct Answer: A

    Solution :

                     \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[n=\frac{T}{{{t}_{1/2}}}=\frac{26}{6.5}=4\] \[\frac{N}{48\times {{10}^{19}}}={{\left( \frac{1}{2} \right)}^{4}}\] \[N=48\times {{10}^{19}}\times \frac{1}{16}\] \[=3\times {{10}^{19}}\]              


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