A) \[Na\]
B) \[O\]
C) \[Cl\]
D) \[N\]
Correct Answer: A
Solution :
\[Na\,(11):\text{ 1}{{\text{s}}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{6}},\text{ }3{{s}^{1}}\] For last electron, \[l=0\] Hence, \[m=0\]
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