question_answer

Hybridisation of\[Fe\]in\[{{K}_{3}}[Fe{{(CN)}_{6}}]\]is

A)  \[s{{p}^{3}}\]                                   

B)  \[{{d}^{2}}s{{p}^{3}}\]

C)  \[s{{p}^{3}}{{d}^{2}}\]                 

D)  \[ds{{p}^{3}}\]

Correct Answer: B

Solution :

                 \[F{{e}^{3+}}:[Ar]3{{d}^{5}}\] Number of ligand = 6 Nature of ligand is strong field. \[F{{e}^{3+}}:\] \[{{[Fe{{(CN)}_{6}}]}^{3-}}:\]                 Hence, hybridization of Fe is\[{{d}^{2}}s{{p}^{3}}\].