A) \[p(1+e)\]
B) \[\frac{p}{1-e}\]
C) \[p\left( \frac{1+e}{1-e} \right)\]
D) \[p\left( 1-\frac{1}{e} \right)\]
Correct Answer: C
Solution :
Change in momentum after 1st impact is \[ep-(-p)=p(1+e)\] After the second impact change in momentum would be \[e(ep)-(-ep)=ep(1+e)\]and so on. Therefore, total change in momentum of ball = momentum imparted to floor \[=p(1+e)[1+e+{{e}^{2}}+....]\] \[=\frac{p(1+e)}{(1-e)}\]
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