A) \[NO_{2}^{+}\]
B) \[N{{O}_{2}}\]
C) \[N{{O}^{+}}\]
D) \[NO_{2}^{-}\]
Correct Answer: A
Solution :
In the nitration of benzene nitronium ion (i.e., \[NO_{2}^{+}\]) acts as a electrophile. \[\underset{conc.}{\mathop{HN{{O}_{3}}}}\,+\underset{conc.}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\xrightarrow{{}}NO_{2}^{+}+{{H}_{2}}\text{O }+\text{ }HSO_{4}^{-}\]
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