BHU PMT BHU PMT (Screening) Solved Paper-2011

  • question_answer
    The radius of earth is 6400 km and\[g=10\] \[m/{{s}^{2}}\]. In order that a body of 5 kg weighs zero at the equator, the angular speed of earth will be

    A)  \[\frac{1}{80}rad/s\]                     

    B)  \[\frac{1}{400}rad/s\]

    C)  \[\frac{1}{800}rad/s\]  

    D)  \[\frac{1}{1600}rad/s\]

    Correct Answer: C

    Solution :

                     Acceleration due to gravity at equator \[g'=g-{{R}_{e}}{{\omega }^{2}}\] For the weight at equator to be zero, \[g'=0\] \[\therefore \]  \[g={{R}_{e}}{{\omega }^{2}}\] or            \[\omega =\sqrt{\frac{g}{{{R}_{e}}}}\]                 \[=\sqrt{\frac{10}{6400\times 1000}}=\frac{1}{80\times 10}\]                 \[=\frac{1}{800}rad/s\]


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