BHU PMT BHU PMT (Screening) Solved Paper-2011

  • question_answer
    A stone is dropped into a well. If the depth of water below the top be h and the velocity of sound is v, then the splash in water is heard after T second. Then

    A)  \[T=\sqrt{\frac{2h}{g}}+\frac{h}{v}\]     

    B)  \[T=2\sqrt{\frac{2h}{g}}\]

    C)  \[T=\frac{2h}{v}\]                          

    D)  \[T=\sqrt{\frac{2h}{g}}\times \frac{h}{v}\]

    Correct Answer: A

    Solution :

                     Required time = time taken by stone to reach the water surface + time taken by sound to reach the top. \[=\sqrt{\frac{2h}{g}}+\frac{\eta }{v}\]


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