BHU PMT BHU PMT (Screening) Solved Paper-2011

  • question_answer
    Energy released in the fission of a single\[_{92}{{U}^{235}}\]nucleus is 200 MeV. The fission rate of\[_{92}{{U}^{235}}\]fuelled reactor operating at power level of 5 MW is

    A)  \[1.56\times {{10}^{14}}/s\]      

    B)  \[1.56\times {{10}^{17}}/s\]

    C)  \[1.56\times {{10}^{20}}/s\]      

    D)  \[1.56\times {{10}^{-17}}/s\]

    Correct Answer: B

    Solution :

                     Energy required per second \[=5MW\] \[=5\times {{10}^{6}}\text{ }J/s\] Energy released during one fission \[=200\text{ }MeV\] \[=200\times 1.6\times {{10}^{-13}}J\] \[\therefore \]Fission rate\[=\frac{5\times {{10}^{6}}}{200\times 1.6\times {{10}^{-13}}}\]                 \[=1.56\times {{10}^{17}}/s\]


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