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BHU PMT BHU PMT (Screening) Solved Paper-2011

  • question_answer
    For a certain organ pipe, three successive resonance frequencies are observed at 425, 595 and 765 Hz respectively. Taking the speed of sound in air to be 340 m/s, determine the fundamental frequency of the pipe

    A)  42.5 Hz                

    B)  85 Hz

    C)  170 Hz                                 

    D)  425 Hz

    Correct Answer: B

    Solution :

                     Observed frequency are 425, 595 and 765 Hz Ratio =425: 595: 768 \[=5\times 87:7\times 85:9\times 85\] \[=5:7:9\] Only odd multiples are obtained. So, the pipe is closed organ pipe and its fundamental frequency is 85 Hz.


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