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  3. BHU PMT

BHU PMT BHU PMT (Screening) Solved Paper-2011

  • question_answer
    A block at rest explodes into 3 parts of the same mass. The momentum of the two parts are - 2pi and pj. The momentum of the third part will have a magnitude

    A)  p                                           

    B)  \[p\sqrt{3}\]

    C)  \[p\sqrt{5}\]                                    

    D)  zero

    Correct Answer: C

    Solution :

                     Let p be the momentum of third part after the explosion of bomb. According to law of conservation of momentum\[-2pi+pj+p=0\]or  \[p=2pi-pj\] So,          \[p=\sqrt{{{(2p)}^{2}}+{{(-p)}^{2}}}=p\sqrt{5}\]


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