BHU PMT BHU PMT (Screening) Solved Paper-2011

  • question_answer
    A particle is moving in a circle of radius r with constant speed v. The change in velocity of particle while moving from A to B\[(<AOB=50{}^\circ )\]is

    A)  \[2v\text{ }cos\text{ }50{}^\circ \]          

    B)  \[2v\text{ }sin\text{ }50{}^\circ \]

    C)  \[2v\text{ }cos25{}^\circ \]       

    D) \[2v\,\sin \,25{}^\circ \]

    Correct Answer: D

    Solution :

                     \[\Delta v=\sqrt{{{v}^{2}}+{{v}^{2}}-2vv\,\cos {{50}^{o}}}\] \[=\sqrt{2}v{{(1-\cos {{45}^{o}})}^{1/2}}\] \[=\sqrt{2}v{{(1-\cos 2\times {{25}^{o}})}^{1/2}}\] \[=\sqrt{2}v{{[1-(1-2{{\sin }^{2}}{{25}^{o}})]}^{1/2}}\] \[=\sqrt{2}v\times \sqrt{2}\sin {{25}^{o}}\] \[=2v\sin {{25}^{o}}\]


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