A) \[\frac{1}{2}(K-1)C{{V}^{2}}\]
B) \[C{{V}^{2}}=\frac{(K-1)}{K}\]
C) \[(K-1)C{{V}^{2}}\]
D) zero
Correct Answer: A
Solution :
On introduction and removal and again an introduction, the capacity and potential remain same. So, net work done by the system in this process \[W={{U}_{f}}-{{U}_{i}}\] \[\frac{1}{2}kC{{V}^{2}}-\frac{1}{2}C{{V}^{2}}=\frac{1}{2}(k-1)C{{V}^{2}}\]
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