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BHU PMT BHU PMT (Screening) Solved Paper-2011

  • question_answer
    A ball is thrown from a point with a speed\[{{v}_{0}}\]at an angle of projection\[\theta \]. From the same point and the same instant, a person starts running with constant speed\[\frac{{{v}_{0}}}{2}\]to catch the ball will the person be able to catch the ball? If yes, what should be the angle of projection?

    A)  Yes, \[60{}^\circ \]                         

    B)  Yes, \[30{}^\circ \]

    C)  No                                        

    D)  Yes,\[45{}^\circ \]

    Correct Answer: A

    Solution :

                     Man will catch the ball if the horizontal component of velocity becomes equal to the constant speed of man \[{{v}_{0}}\cos \theta =\frac{{{v}_{0}}}{2}\]                 \[\cos \theta =\frac{1}{2}\]                 \[\cos \theta =\cos {{60}^{o}}\]                 \[\theta ={{60}^{o}}\]


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