A) \[\frac{1}{3}({{K}_{1}}+2{{K}_{2}})\]
B) \[\frac{1}{2}(2{{K}_{1}}+3{{K}_{2}})\]
C) \[\frac{1}{4}(3{{K}_{2}}+2{{K}_{1}})\]
D) \[\frac{1}{4}({{K}_{1}}+3{{K}_{2}})\]
Correct Answer: D
Solution :
Both the cylinders are in parallel, for the heat flow from one end as shown Hence,\[{{K}_{eq}}=\frac{{{K}_{1}}{{A}_{1}}+{{K}_{2}}{{A}_{2}}}{{{A}_{1}}+{{A}_{2}}};\]where\[{{A}_{1}}=\]area of cross-section of inner cylinder\[=\pi {{R}^{2}}\]and \[{{A}_{2}}=\]area of cross-section of cylindrical shell \[=\pi \{{{(2R)}^{2}}-{{(R)}^{2}}\}=3\pi {{R}^{2}}\] \[\Rightarrow \] \[{{K}_{eq}}=\frac{{{K}_{1}}(\pi {{R}^{2}})+{{K}_{2}}(3\pi {{R}^{2}})}{\pi {{R}^{2}}+3\pi {{R}^{2}}}\] \[=\frac{{{K}_{1}}+3{{K}_{2}}}{4}\]You need to login to perform this action.
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