A) The pressure exerted by hydrogen is half that exerted by helium
B) The pressure exerted by hydrogen is equal to that exerted by helium
C) Average KE of the molecule of hydrogen is half the average KE of the molecules of helium
D) The pressure exerted by hydrogen is twice that exerted by helium
Correct Answer: D
Solution :
\[pV=nRT\] \[{{p}_{{{H}_{2}}}}=\frac{m}{{{M}_{{{H}_{2}}}}}.\frac{RT}{V}\] \[{{p}_{He}}=\frac{m}{{{M}_{He}}}.\frac{RT}{V}\] \[\therefore \] \[\frac{{{P}_{{{H}_{2}}}}}{{{P}_{He}}}=\frac{{{M}_{He}}}{{{M}_{{{H}_{2}}}}}=\frac{4\times {{10}^{-3}}}{2\times {{10}^{-3}}}=2\] \[\Rightarrow \] \[{{p}_{{{H}_{2}}}}=2{{P}_{He}}\]
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