A) \[{{F}^{-}}\]
B) \[O{{H}^{-}}\]
C) \[NH_{2}^{-}\]
D) \[CH_{3}^{-}\]
Correct Answer: D
Solution :
Stronger the base, higher the electron releasing tendency. Conjugate base of a weak acid is strong or vice-versa. \[\therefore \]The order of their acids is \[HF>{{H}_{2}}O>C{{H}_{4}}>N{{H}_{3}}\] \[\therefore \]The order of basic strength is \[{{F}^{-}}<O{{H}^{-}}<CH_{3}^{-}<NH_{2}^{-}\] But the electronegativity of carbon is less than that of nitrogen, hence,\[CH_{3}^{-}\]is a stronger base than\[N{{H}_{2}}\]. Therefore,\[CH_{3}^{\text{O-}}\]has highest electron releasing tendency.
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