A) same as for smaller droplet
B) \[\frac{1}{2}\]of that for smaller droplet
C) \[\frac{1}{4}\]of that for smaller droplet
D) twice that for smaller droplet
Correct Answer: B
Solution :
Volume of big drop = Volume of 8 droplets ie, \[\frac{4}{3}\pi {{R}^{3}}=8\times \frac{4}{3}\pi {{r}^{3}}\] \[\therefore \] \[r=\frac{R}{2}\] For smaller drop, \[\Delta {{P}_{s}}=\frac{2T}{r}=\frac{2T}{R/2}=\frac{4T}{R}\] For bigger drop, \[\Delta {{P}_{b}}=\frac{2T}{R}=\frac{2T}{R}=\frac{1}{2}\Delta {{P}_{s}}\]
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