A) \[{{r}^{3/2}}\]
B) r
C) \[{{r}^{2/3}}\]
D) \[{{r}^{1/2}}\]
Correct Answer: A
Solution :
If\[I\]is the safe current through the fuse wire and h is the rate of loss of heat in steady state, \[{{I}^{2}}R=hA\] Or \[{{I}^{2}}\left( \frac{\rho L}{\pi {{r}^{2}}} \right)=h\times 2\pi rL\] Or \[I\propto {{r}^{3/2}}\]
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