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BHU PMT BHU PMT (Screening) Solved Paper-2005

  • question_answer
    Given pH of a solution A is 3 and it is mixed with another solution B having pH 2. If both mixed, then resultant pH of the solution will be:

    A)  3.2                                        

    B)  1.9

    C)  3.4                                        

    D)  3.5

    Correct Answer: B

    Solution :

                     pH of solution A = 3, pH of solution B = 2 \[\therefore \] \[[H]={{10}^{-3}}M,\text{  }\!\![\!\!\text{ }H]={{10}^{-2}}M,\] Total      \[[{{H}^{+}}]={{10}^{-3}}+{{10}^{-2}}=11\times {{10}^{-3}}\] \[pH=-\log [{{H}^{+}}]=-\log 11\times {{10}^{-3}}\] \[=3-log\text{ }11\] \[=3-1.04=1.96\]


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