BHU PMT BHU PMT (Screening) Solved Paper-2005

  • question_answer
    A light passing through air has wavelength \[6000\overset{\text{o}}{\mathop{\text{A}}}\,\]. The wavelength when same ray passes through a glass slab of refractive index 1.5 will be:

    A) \[2000\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B) \[4000\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[8000\overset{\text{o}}{\mathop{\text{A}}}\,\]             

    D) \[1200\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: B

    Solution :

    From Hygen's wave theory, we have \[_{1}{{n}_{2}}=\frac{{{v}_{1}}(speed\text{ }of\text{ }light\text{ }in\text{ }air)}{{{v}_{2}}(speed\text{ }of\text{ }light\text{ }in\text{ }glass)}=\frac{{{\lambda }_{a}}}{{{\lambda }_{g}}}\] \[1.5=\frac{6000}{{{\lambda }_{g}}}\] \[\Rightarrow \]  \[{{\lambda }_{g}}=\frac{6000}{1.5}=4000\overset{\text{o}}{\mathop{\text{A}}}\,\]            


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