A) pyridinium chloro chromate
B) chromic anhydride in glacial acetic acid
C) acidic dichromate
D) acidic permanganate
Correct Answer: A
Solution :
Sol. Pyridinium chlorochromate oxidises an alcoholic group selectively in the presence of carbon-carbon double bond. \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-CH=CH-C{{H}_{3}}\xrightarrow[{}]{PCC}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\mathop{CH}}\,-CH=CH-C{{H}_{3}}\]
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