BHU PMT BHU PMT (Mains) Solved Paper-2010

  • question_answer
    An athlete throws a discus from rest to a final angular velocity of\[15\text{ }rad\text{ }{{s}^{-1}}\]in 0.270 s before releasing it. During acceleration, discus moves a circular arc of radius 0.810 m. Acceleration of discus before it is released is

    A) \[45\text{ }m{{s}^{-2}}\]              

    B) \[182\text{ }m{{s}^{-2}}\]

    C)  \[187m{{s}^{-2}}\]         

    D) \[192m{{s}^{-2}}\]

    Correct Answer: A

    Solution :

                     Given, angular velocity,\[\omega =15\text{ }rad/\text{ }s\] Time,\[t=0.270\text{ }s\] Radius,\[r=0.810\text{ }m\] Acceleration, \[a=\frac{v}{t}\] or                  \[a=\frac{r\omega }{t}\]                \[[\because v=r\omega ]\]                                 \[a=\frac{0.810\times 15}{0.270}\] \[=45m/{{s}^{2}}\]


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