A) \[{{N}_{3}}\]and\[NC{{l}_{3}}\]
B) \[{{N}_{2}}\]and\[HCl\]
C) \[{{N}_{3}}\]and\[N{{H}_{4}}Cl\]
D) \[NC{{l}_{3}}\]and\[HCl\]
Correct Answer: D
Solution :
When ammonia reacts with excess of chlorine, nitrogen trichloride and\[HCl\]are obtained as main product. \[N{{H}_{3}}+\underset{(excess)}{\mathop{3C{{l}_{2}}}}\,\xrightarrow{{}}NC{{l}_{3}}+3HCl\] In the above reaction, if\[N{{H}_{3}}\]is in excess,\[N{{H}_{4}}Cl\]and\[{{N}_{2}}\]are the main products.
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