BHU PMT BHU PMT (Mains) Solved Paper-2010

  • question_answer
    Copper has face centred cubic (fee) lattice with interatomic spacing equals to \[2.54\,\overset{\text{o}}{\mathop{\text{A}}}\,\]. The value of lattice constant for this lattice is

    A) \[3.59\,\overset{\text{o}}{\mathop{\text{A}}}\,\]       

    B) \[2.54\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[1.27\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D) \[5.08\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: A

    Solution :

    The value of lattice constant \[a=\frac{4r}{\sqrt{2}}\] \[=2\sqrt{2}\times r\] \[=2\sqrt{2}\times 2.54/2\] \[=3.59\text{ }A\]


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